【单选题】109 / 121湍流平板边界层的局部阻力系数(1/7 幂次剖面)为ACf=0.0578 Rex−1/5C_f=0.0578\,Re_x^{-1/5}Cf=0.0578Rex−1/5正确BCf=0.664 Rex−1/2C_f=0.664\,Re_x^{-1/2}Cf=0.664Rex−1/2CCf=0.074 Rex−1/5C_f=0.074\,Re_x^{-1/5}Cf=0.074Rex−1/5DCf=0.0578 Rex1/5C_f=0.0578\,Re_x^{1/5}Cf=0.0578Rex1/5参考答案A参考解析Cf=0.0578 Rex−1/5C_f=0.0578\,Re_x^{-1/5}Cf=0.0578Rex−1/5(K9−46K9-46K9−46)。