【单选题】6 / 23矩形截面受扭塑性抵抗矩WtW_tWt(h≥bh \ge bh≥b)为?Ab2(3h−b)/6b^2(3h-b)/6b2(3h−b)/6正确Bbh2/6bh^2/6bh2/6Cbh/2bh/2bh/2Db2h/2b^2 h/2b2h/2参考答案A参考解析Wt=b2(3h−b)/6W_t = b^2(3h - b)/6Wt=b2(3h−b)/6。